Higher-Order Derivatives
Compute second, third, and nth derivatives. Interpret the second derivative as the rate of change of the rate of change (acceleration in motion problems). Introduce the notation f''(x), d²y/dx², and y''.
A lesson of Calculus, in The Chain Rule and Advanced Differentiation, about 10 minutes.
By the end of this lesson, you will be able to compute higher-order derivatives, interpret them physically (velocity, acceleration, jerk), and find patterns in higher-order derivatives of elementary functions.
Notation
$$f''(x) = \frac{d^2y}{dx^2} = \frac{d^2f}{dx^2} = D^2f$$
$$f^{(n)}(x) = \frac{d^n y}{dx^n} \quad \text{(}n\text{th derivative)}$$
Physical Interpretation
For position $s(t)$:
- $v(t) = s'(t)$: velocity (rate of change of position)
- $a(t) = v'(t) = s''(t)$: acceleration (rate of change of velocity)
- $j(t) = a'(t) = s'''(t)$: jerk (rate of change of acceleration)
Positive acceleration: speeding up in the positive direction (or slowing down in the negative direction).
Example 1 — Polynomial
$f(x) = 3x^5 - 2x^3 + x$
$f'(x) = 15x^4 - 6x^2 + 1$
$f''(x) = 60x^3 - 12x$
$f'''(x) = 180x^2 - 12$
$f^{(4)}(x) = 360x$
$f^{(5)}(x) = 360$
$f^{(6)}(x) = 0$
Degree-$n$ polynomial: $n$th derivative is constant, $(n+1)$th is zero.
Example 2 — Trigonometric Patterns
$$\sin x \to \cos x \to -\sin x \to -\cos x \to \sin x \to \cdots$$
Period 4: $(\sin x)^{(n)}$ depends on $n \mod 4$:
- $n \equiv 0$: $\sin x$
- $n \equiv 1$: $\cos x$
- $n \equiv 2$: $-\sin x$
- $n \equiv 3$: $-\cos x$
Similarly for $\cos x$ (offset by one).
Example 3 — Exponential
$\dfrac{d^n}{dx^n}[e^x] = e^x$ for all $n$.
$\dfrac{d^n}{dx^n}[e^{ax}] = a^n e^{ax}$
Example 4 — Physical Motion
$s(t) = t^3 - 6t^2 + 9t$:
$v(t) = 3t^2 - 12t + 9 = 3(t-1)(t-3)$
$a(t) = 6t - 12$
At $t = 0$: $v = 9$ (moving positive), $a = -12$ (decelerating).
At $t = 1$: $v = 0$ (momentarily at rest), $a = -6$ (still decelerating).
At $t = 2$: $v = -3$ (moving negative), $a = 0$ (inflection in velocity).
Second Derivative and Concavity (Preview)
$f''(x) > 0$: $f$ is concave up (slope is increasing, bowl opening upward)
$f''(x) < 0$: $f$ is concave down (slope is decreasing, bowl opening downward)