Connecting f, f', and f'' in Graph Analysis
Integrate information from f, f', and f'' to sketch graphs and to draw conclusions about each function from graphs of the others. This is the highest-frequency topic on the AP Calculus AB exam and requires fluency in all directions.
A lesson of AP Calculus AB, in Analytical Applications of Differentiation, about 10 minutes.
Curve Sketching Using Calculus
By the end of this lesson, you will be able to analyze a function comprehensively using limits, derivatives, and asymptotes to produce an accurate sketch.
The Calculus Approach to Curve Sketching
Calculus lets us go far beyond a table of values. By analyzing $f$, $f'$, and $f''$, we can determine the complete behavior of the curve.
The Checklist
1. Domain: where is $f(x)$ defined?
2. Intercepts:
- x-intercepts: solve $f(x) = 0$
- y-intercept: $f(0)$ (if in domain)
3. Symmetry:
- Even ($f(-x) = f(x)$) → symmetric about y-axis
- Odd ($f(-x) = -f(x)$) → symmetric about origin
4. Asymptotes:
- Vertical: $\lim_{x\to a^\pm} f(x) = \pm\infty$ (denominator = 0, numerator ≠ 0)
- Horizontal: $\lim_{x\to\pm\infty} f(x)$
- Oblique: if degree of numerator = degree of denominator + 1, perform polynomial division
5. Increasing/Decreasing: Find $f'(x)$; set = 0 or find where undefined; sign chart.
6. Local Extrema: At critical points: first derivative test (sign change of $f'$) or second derivative test ($f''(c)$ sign).
7. Concavity and Inflection Points: Find $f''(x)$; sign chart; inflection where concavity changes.
8. Sketch: use all the above information.
Example: $f(x) = \frac{x^2}{x^2 - 4}$
1. Domain: $x \neq \pm 2$ → $(-\infty,-2) \cup (-2,2) \cup (2,\infty)$
2. Intercepts: $f(0) = 0/(-4) = 0$ (y-intercept and x-intercept)
3. Symmetry: $f(-x) = (-x)^2/((-x)^2-4) = x^2/(x^2-4) = f(x)$ → even; symmetric about y-axis
4. Asymptotes:
- Vertical: $x = \pm 2$ (denominator = 0, numerator = 4 ≠ 0)
- Horizontal: $\lim_{x\to\pm\infty}\frac{x^2}{x^2-4} = 1$ → $y = 1$
5. $f'(x)$: Using quotient rule:
$f'(x) = \frac{2x(x^2-4) - x^2(2x)}{(x^2-4)^2} = \frac{-8x}{(x^2-4)^2}$