Graphing Polynomial Functions
Sketch polynomial graphs using zeros (with multiplicity), end behavior, and the y-intercept. Understand that even-multiplicity zeros "touch" the x-axis and odd-multiplicity zeros "cross" it.
A lesson of Algebra 2, in Polynomial Functions, about 10 minutes.
By the end of this lesson, you will be able to sketch polynomial graphs using zeros (with multiplicity), $y$-intercept, end behavior, and turning points, and identify local and global features from graphs.
The Big Idea
Graphing a polynomial without a calculator is a synthesis of everything in this unit: end behavior (degree + leading coefficient), $x$-intercepts (zeros + multiplicity), $y$-intercept, and a rough count of turning points. These features, plotted in order, produce an accurate qualitative sketch.
The Complete Graphing Procedure
- End behavior from degree and leading coefficient
- $x$-intercepts from the zeros (and multiplicity for cross vs. bounce)
- $y$-intercept by evaluating $f(0)$
- Turning points — at most $n-1$ for degree $n$
- Sign analysis — determine whether $f$ is positive or negative in each interval between zeros
- Sketch — connect the information
Example 1 — Step-by-Step Sketch
Graph $f(x) = (x+2)(x-1)^2(x-4)$
Step 1 — End behavior:
Degree: $1+2+1 = 4$ (even); leading coefficient: positive (all factors have positive leading terms).
Both tails up.
Step 2 — Zeros:
$x = -2$ (mult. 1) → crosses
$x = 1$ (mult. 2) → bounces
$x = 4$ (mult. 1) → crosses
Step 3 — $y$-intercept:
$f(0) = (2)(1)(-4) = -8$ → $(0, -8)$
Step 4 — Sign analysis (between zeros):
- $x < -2$: all tails up from the right → positive (both tails up, degree 4 positive)
- $-2 < x < 1$: test $x = 0$: $f(0) = -8 < 0$ → negative
- $1 < x < 4$: test $x = 2$: $f(2) = (4)(1)(-2) = -8 < 0$ → negative (bounce at $x=1$ keeps same sign)
- $x > 4$: positive (right tail up)
Sketch: comes from upper-left, crosses $x$-axis at $-2$, dips below, bounces off at $x = 1$, continues below, crosses at $x = 4$, rises to upper-right.
Example 2 — Identifying Graph Features
$g(x) = -2x^3 + 6x^2 - 4x$.
Factor: $g(x) = -2x(x^2 - 3x + 2) = -2x(x-1)(x-2)$
Zeros: $x = 0, 1, 2$ (all mult. 1 → all cross)
Degree 3, negative leading → left up, right down.
$y$-intercept: $g(0) = 0$ (on the $x$-axis)
Sign test ($x = 0.5$): $g(0.5) = -2(0.5)(−0.5)(−1.5) = -2(0.5)(0.75) = -0.75 < 0$