Compound Inequalities
Solve and graph "and" (conjunction) and "or" (disjunction) compound inequalities. Understand the difference between an intersection and a union of solution sets and interpret both in real-world contexts.
A lesson of Algebra 1, in Linear Inequalities & Absolute Value, about 30 minutes.
By the end of this lesson, you will be able to solve and graph "and" inequalities as a single three-part statement, solve "or" inequalities as two separate ones, and say what each kind of solution set means in a real constraint.
Two Conditions at Once
Most real constraints come in pairs.
A reaction must run at $150°C$ or hotter, and at $200°C$ or cooler.
A driver is pulled over for going under $45$ mph, or over $65$ mph.
Those two sentences look similar and behave completely differently. The first needs both conditions true together. The second needs only one of them true.
| Word | What it demands | The picture |
|---|---|---|
| and | Both at once | A segment between two points |
| or | At least one | Two rays pointing away from each other |
Getting the word right is most of the work. Everything after it is inequality solving you already know.
"And": One Statement in Three Parts
An "and" inequality is written as a single sandwich:
$$-3 \leq 2x + 1 < 9$$
Read it as two claims about the same thing: $2x + 1$ is at least $-3$, and $2x + 1$ is below $9$.
To solve it, do everything to all three parts. The middle is where the variable lives, and the two outer parts have to keep up with it or the sandwich stops meaning what it meant.
"Or": Two Statements, Solved Separately
An "or" inequality is genuinely two problems:
$$2x + 1 < -5 \quad \text{or} \quad 3x - 2 \geq 7$$
Solve each one on its own, then put the two answers side by side. There is no sandwich to write, because the two solution sets do not touch. Between them sits a gap of numbers that satisfy neither.
The two pieces are joined with the union symbol $\cup$, which just means "and also these":
$$(-\infty, -3) \cup [3, \infty)$$
Example 1: An "And", Worked All the Way Through
Solve $-3 \leq 2x + 1 < 9$. Every move happens three times, once on each part.
- Subtract 1 from all three parts -4 <= 2x < 8